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(F)=F^2+20F-86
We move all terms to the left:
(F)-(F^2+20F-86)=0
We get rid of parentheses
-F^2+F-20F+86=0
We add all the numbers together, and all the variables
-1F^2-19F+86=0
a = -1; b = -19; c = +86;
Δ = b2-4ac
Δ = -192-4·(-1)·86
Δ = 705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{705}}{2*-1}=\frac{19-\sqrt{705}}{-2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{705}}{2*-1}=\frac{19+\sqrt{705}}{-2} $
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